| Syllabus | Alternate Universe Cambridge 0610 |
| Subject | Biology (0610) Extended |
| Paper | 0610/21/M/J/25 · Paper 2, Variant 1 |
| Also listed as | 0610_s25_qp_21 · 0610_s25_ms_21 |
| Session | May/June 2025 |
| Questions | 40, multiple choice, with answers and explanations |
| Cost | Free |
0610/21/M/J/25 answer key
- Q1 A
- Q2 A
- Q3 A
- Q4 A
- Q5 A
- Q6 A
- Q7 A
- Q8 A
- Q9 A
- Q10 A
- Q11 A
- Q12 A
- Q13 A
- Q14 A
- Q15 A
- Q16 A
- Q17 A
- Q18 A
- Q19 A
- Q20 A
- Q21 A
- Q22 A
- Q23 A
- Q24 A
- Q25 A
- Q26 A
- Q27 A
- Q28 A
- Q29 A
- Q30 A
- Q31 A
- Q32 A
- Q33 A
- Q34 A
- Q35 A
- Q36 A
- Q37 A
- Q38 A
- Q39 A
- Q40 A
Preview the first questions
Question 1
Which characteristic of living organisms requires carbon dioxide to diffuse into a leaf?
- nutrition
- excretion
- movement
- respiration
Show the answer and explanation
Correct answer: A
Step 1: A leaf takes in carbon dioxide to make food by photosynthesis, which is the plant form of nutrition. Step 2: So the characteristic that requires carbon dioxide to diffuse into a leaf is nutrition. Step 3: Excretion, movement and respiration do not need carbon dioxide to enter the leaf; respiration in fact releases carbon dioxide.
Question 2
Which set of features is characteristic only of birds?
- hard-shelled eggs and feathers
- hair and wings
- scales and soft-shelled eggs
- wings and soft-shelled eggs
Show the answer and explanation
Correct answer: A
Step 1: Birds are the only group with feathers, and they lay hard-shelled eggs. Step 2: So hard-shelled eggs and feathers together are characteristic only of birds. Step 3: Hair is a mammal feature, wings are also found in insects and bats, and soft-shelled eggs are laid by reptiles.
Question 3
Which structures are found in both plant cells and animal cells?
- cell membranes and nuclei
- cell walls and cell membranes
- nuclei and cell walls
- cytoplasm and chloroplasts
Show the answer and explanation
Correct answer: A
Step 1: Both plant and animal cells have a cell membrane and a nucleus. Step 2: So cell membranes and nuclei are found in both types of cell. Step 3: Cell walls and chloroplasts are found only in plant cells, so any pair including them is not common to both.
Worked answers: questions 4 to 40
Why each answer is right. The full questions are waiting in every Paperverse world, with your mark at the end.
Question 4 · Answer A
Step 1: Active transport moves particles from a low to a high concentration, so statement 1 is correct and statement 2 is wrong. Step 2: It needs energy from respiration, so statement 3 is correct, and because it needs respiration it can only happen in living cells, so statement 4 is correct. Step 3: Therefore statements 1, 3 and 4 are correct.
Question 5 · Answer A
Step 1: In DNA the bases pair in a fixed way: adenine pairs with thymine, and cytosine pairs with guanine. Step 2: So thymine and adenine form a correct base pair. Step 3: The other combinations mix bases that do not pair together.
Question 6 · Answer A
Step 1: Protein is detected with the biuret test, which does not need heating. Step 2: A positive biuret test changes the colour from blue to purple. Step 3: The Benedict’s test is for reducing sugars, needs heating and gives a brick-red colour, so it is not the protein test.
Question 7 · Answer A
Step 1: Above its optimum temperature an enzyme is denatured, which changes the shape of its active site. Step 2: With a changed active site the substrate no longer fits, so fewer reactions occur and activity falls. Step 3: Enzymes are not alive so cannot be killed, they are not used up, and faster-moving reactants would increase activity, not lower it.
Question 8 · Answer A
Step 1: Spongy mesophyll has many air spaces that allow efficient gas exchange. Step 2: The long, rectangular cells packed with chloroplasts to absorb light are the palisade mesophyll, not the spongy mesophyll. Step 3: So spongy mesophyll has air spaces but not long rectangular light-absorbing cells.
Question 9 · Answer A
Step 1: The child eats more vitamin C (54 mg) than the RDA (50 mg) and exactly the RDA of iron (11 mg), so scurvy and anaemia are not risks. Step 2: The child eats only 5 units of vitamin D against an RDA of 10, so vitamin D is short, which causes rickets. Step 3: Therefore only condition 2, rickets, is a risk.
Question 10 · Answer A
Step 1: Assimilation is the taking in and use of absorbed nutrients by the cells of the body. Step 2: So the uptake and use of nutrients by cells is assimilation. Step 3: Absorption is the movement of nutrients into the blood, ingestion is taking food into the body, and egestion is removing undigested waste.
Question 11 · Answer A
Step 1: Trypsin is a protease, so it breaks down protein. Step 2: Trypsin is made in the pancreas and works in the small intestine, so it breaks down protein in the small intestine. Step 3: Maltose is broken down by maltase, and the protease in the stomach is pepsin, not trypsin.
Question 12 · Answer A
Step 1: The lacteal is a lymph vessel that absorbs the products of fat digestion. Step 2: It runs up the centre of each villus, so the central vessel is the lacteal. Step 3: The outer layer is the epithelium where absorption occurs, and the surrounding capillaries carry away glucose and amino acids.
Question 13 · Answer A
Step 1: Transpiration depends on water vapour diffusing out of the leaf into the air. Step 2: Higher humidity means more water vapour already in the air, so the concentration gradient is smaller and transpiration falls. Step 3: So as humidity increases the rate of transpiration falls steadily.
Question 14 · Answer A
Step 1: A source makes or releases sugars, and a sink uses or stores them. Step 2: In spring the green leaves photosynthesise and export sugars, so they are sources. Step 3: The growing flowers use up sugars, so they are sinks.
Question 15 · Answer A
Step 1: In a single circulation the blood passes through the heart only once per circuit. Step 2: Blood leaving the heart goes first to the gills to be oxygenated, then on to the body, including the muscles. Step 3: From the muscles it returns straight to the heart, so the order is gills, muscles, heart.
Question 16 · Answer A
Step 1: The structures detected on a pathogen are its antigens, so W is antigens. Step 2: Antibodies are made to destroy pathogens directly, so X is antibodies, and the cells that engulf marked pathogens are phagocytes, so Y is phagocytes. Step 3: The cells kept for long-term immunity are memory cells, so Z is memory cells.
Question 17 · Answer A
Step 1: The cholera toxin acts on the wall of the gut. Step 2: It causes water to move out of the blood and into the gut. Step 3: This extra water in the gut produces severe watery diarrhoea, which can cause dehydration.
Question 18 · Answer A
Step 1: A decreasing lung volume means the person is breathing out. Step 2: Quiet expiration is passive: the diaphragm relaxes and the external intercostal muscles relax, so the ribs fall and the chest volume decreases. Step 3: So at point X the diaphragm and the external intercostal muscles are both relaxing.
Question 19 · Answer A
Step 1: Cell division and muscle contraction both need energy released by respiration. Step 2: Diffusion and osmosis are passive processes that do not require energy from respiration. Step 3: So only processes 1 and 3 require energy from respiration.
Question 20 · Answer A
Step 1: The glomerulus is a knot of capillaries where blood is filtered under pressure. Step 2: Small molecules such as water, glucose, urea and ions are filtered out of the blood into the tubule. Step 3: Reabsorption happens later along the tubule, protein synthesis happens at ribosomes, and deamination happens in the liver.
Question 21 · Answer A
Step 1: The small sac in the ending of neurone 1 that stores the chemical is a vesicle, so P is a vesicle. Step 2: The chemical released into the gap is the neurotransmitter (Q), and the gap itself is the synaptic gap (R). Step 3: The site on neurone 2 that the chemical binds to is the receptor, so S is the receptor.
Question 22 · Answer A
Step 1: Rod cells are very sensitive to dim light, so they are used for night vision. Step 2: Rod cells cannot tell colours apart; colour vision is the job of cone cells. Step 3: So rod cells are used for night vision but not for colour vision.
Question 23 · Answer A
Step 1: The glands on top of the kidneys are the adrenal glands, which release adrenaline. Step 2: Adrenaline prepares the body for action, widening the pupils to let in more light. Step 3: Adrenaline also increases heart rate and blood glucose, so the decreases listed are wrong, and sexual characteristics develop in response to sex hormones.
Question 24 · Answer A
Step 1: When the body overheats, the arterioles supplying the skin capillaries widen, which is vasodilation. Step 2: More blood then flows near the skin surface, so more heat is lost to the surroundings. Step 3: Vasoconstriction would reduce heat loss (a response to cold), and it is the arterioles, not the veins, that control this flow.
Question 25 · Answer A
Step 1: A tropism is a growth response to a stimulus, and phototropism is a response to light. Step 2: A shoot growing towards light is phototropism. Step 3: Growth in response to gravity is gravitropism, and reactions using light such as photosynthesis are not tropisms.
Question 26 · Answer A
Step 1: Antibiotics work on structures and processes found in bacteria, so they kill bacteria. Step 2: Viruses do not have these structures, so antibiotics have no effect on viruses. Step 3: So antibiotics kill bacteria but do not affect viruses.
Question 27 · Answer A
Step 1: Producing offspring from one parent by budding is asexual reproduction. Step 2: Asexual reproduction involves no gametes, so the offspring is genetically identical to the parent. Step 3: So the parent and offspring are genetically identical and this is asexual reproduction.
Question 28 · Answer A
Step 1: A sharp peak at about day 14 is the LH surge that triggers ovulation, so W is LH. Step 2: Oestrogen rises during the first half of the cycle and peaks just before day 14, so the gradually rising curve Y is oestrogen. Step 3: Progesterone rises in the second half of the cycle, so neither curve here is progesterone.
Question 29 · Answer A
Step 1: Mitosis copies every chromosome and shares the copies equally between two daughter cells. Step 2: Each daughter cell therefore has the same number of chromosomes as the parent and an identical set. Step 3: Halving the chromosome number happens in meiosis, and the number is never doubled in the daughter cells.
Question 30 · Answer A
Step 1: The first cross gives a mixture of red and white hair (roan), so neither allele is fully dominant; both are expressed together, which is codominance. Step 2: Crossing two roan (heterozygous) cattle then gives 1 red : 2 roan : 1 white, the ratio expected from codominance. Step 3: If one colour were dominant the offspring would not show the blended roan phenotype.
Question 31 · Answer A
Step 1: All body cells from the same organism contain the same genes, so statement 2 is correct. Step 2: A specialised cell only switches on (expresses) the genes for the proteins it needs, so statement 3 is correct. Step 3: Different specialised cells express different genes, so statement 1 is wrong.
Question 32 · Answer A
Step 1: In a hot, dry habitat a plant must reduce water loss. Step 2: Few stomata, a thick waxy cuticle and a small surface area all reduce the amount of water lost. Step 3: Many stomata, a thin cuticle or a large surface area would all increase water loss, so they are not suited to dry habitats.
Question 33 · Answer A
Step 1: Natural selection happens without human involvement, driven by the environment. Step 2: Wild animals evolving long necks to reach high leaves is natural selection with no humans involved. Step 3: Artificial selection is carried out by humans, antibiotic resistance arises by natural selection, and making insulin is genetic engineering, so the other rows are mismatched.
Question 34 · Answer A
Step 1: A pyramid of energy has a bar for each trophic level whose size shows the energy at that level. Step 2: So it shows the energy stored at each trophic level. Step 3: It does not directly show the energy lost between levels, the input from the Sun, or one total for the whole ecosystem.
Question 35 · Answer A
Step 1: A secondary consumer eats a primary consumer. The sea otter, seal, sea lion and orca whale all eat primary consumers, so there are four secondary consumers. Step 2: A tertiary consumer eats a secondary consumer. Only the orca whale eats the seal and sea lion (which are secondary consumers), so there is one tertiary consumer. Step 3: So there are four secondary consumers and one tertiary consumer.
Question 36 · Answer A
Step 1: Nitrate appeared only in the unheated soil, so something in that soil turned the added ammonium into nitrate. Step 2: Nitrifying bacteria convert ammonium ions into nitrate ions; heating to 100 degrees Celsius killed them in the heated sample, so no nitrate formed. Step 3: All nitrate had already been removed, so it was not broken down, and ammonium was added directly, so nitrogen fixation was not needed.
Question 37 · Answer A
Step 1: The lag phase is the first part of the curve, where the population grows only slowly as organisms adjust and begin to reproduce. Step 2: So the region at the very start, where the population rises slowly, is the lag phase. Step 3: The steeply rising part is the exponential (log) phase, and the flat top is the stationary phase.
Question 38 · Answer A
Step 1: Biodiversity is the number of different species found in an area. Step 2: So the term for the number of different species living in an area is biodiversity. Step 3: Conservation is protecting species, an ecosystem is a community plus its environment, and a population is all the members of one species.
Question 39 · Answer A
Step 1: Eutrophication is caused by extra nutrients, such as nitrates, entering water. Step 2: Sewage adds these nutrients to water, so it can cause eutrophication. Step 3: Carbon dioxide and methane are greenhouse gases, and non-biodegradable plastic pollutes physically, so none of these cause eutrophication.
Question 40 · Answer A
Step 1: First the plasmid is cut open with restriction enzymes (process 1) so the human gene can be added. Step 2: The recombinant plasmids are then inserted into bacteria (process 3), and those bacteria are allowed to multiply (process 4). Step 3: Finally the bacteria express the human gene to make insulin (process 2), giving the order 1, 3, 4, 2.